1) transform grams that propane (C3H8) to moles of propane using conversion factors:
The molar massive of C3H8 is 3(12.01 g) + 8(1.008 g) = 44.09 g, so:
86.6 g C3H8 × (1 mole C3H8/44.09 g) = 1.964 moles C3H8
2) transform moles the propane to mole of oxygen (O2) based upon the stoichiometry that the balanced equation:
There are 5 mole of O2 for every 1 mole of propane, so:
1.964 moles C3H8 × (5 mole O2/1 mole C3H8) = 9.82 mole O2
3) transform moles of oxygen come grams of oxygen using conversion factors:
The molar massive of O2 is 2(16.00 g) = 32.00 g, so:
9.82 mole O2 × (32.00 g/1 mole O2) = 314 g O2
The last answer is 314 g!
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